m= 10 kg,u= 0 (Since the dumb-bell falls from rest) Distance covered, s= 80cm = 0.8m a= 10 ms-2
From equation of motion, v2=u2+ 2as
v2= 0 + 2 × 10 × 0.8
= 16 = v = \(\sqrt{16}\) = 4ms-1
Momentum of dumb-bell just before it touches the floor
p = mv = 10 × 4 = 40 kg-ms-1
When the dumb-bell touches the floor, its velocity becomes zero. Thus, the total momentum of the dumb-bell is transferred to the floor. Hence, the momentum transferred to floor = 40 kg-ms-1.
Use these adverbs to fill in the blanks in the sentences below.
awfully sorrowfully completely loftily carefully differently quickly nonchalantly
(i) The report must be read ________ so that performance can be improved.
(ii) At the interview, Sameer answered our questions _________, shrugging his shoulders.
(iii) We all behave _________ when we are tired or hungry.
(iv) The teacher shook her head ________ when Ravi lied to her.
(v) I ________ forgot about it.
(vi) When I complimented Revathi on her success, she just smiled ________ and turned away.
(vii) The President of the Company is ________ busy and will not be able to meet you.
(viii) I finished my work ________ so that I could go out to play
The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. They were first disclosed by English physicist and mathematician Isaac Newton.
Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.
Newton's 2nd law of motion deals with the relation between force and acceleration. According to the second law of motion, the acceleration of an object as built by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
Newton's 3rd law of motion states when a body applies a force on another body that there is an equal and opposite reaction for every action.