Question:

How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s–2.

Updated On: Nov 21, 2023
Hide Solution
collegedunia
Verified By Collegedunia

Solution and Explanation

m= 10 kg,u= 0 (Since the dumb-bell falls from rest) Distance covered, s= 80cm = 0.8m a= 10 ms-2 
From equation of motion, v2=u2+ 2as 
v2= 0 + 2 × 10 × 0.8
= 16 = v = \(\sqrt{16}\) = 4ms-1
Momentum of dumb-bell just before it touches the floor
p = mv = 10 × 4 = 40 kg-ms-1
When the dumb-bell touches the floor, its velocity becomes zero. Thus, the total momentum of the dumb-bell is transferred to the floor. Hence, the momentum transferred to floor = 40 kg-ms-1.

Was this answer helpful?
0
0

Concepts Used:

Laws of Motion

The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. They were first disclosed by English physicist and mathematician Isaac Newton.

Newton’s First Law of Motion

Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.

Newton’s Second Law of Motion

Newton's 2nd law of motion deals with the relation between force and acceleration. According to the second law of motion, the acceleration of an object as built by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Newton’s Third Law of Motion

Newton's 3rd law of motion states when a body applies a force on another body that there is an equal and opposite reaction for every action.