Question:

How much gram of ethanol is required to obtain 280 ml dihydrogen at S.T.P by reaction of C2H5OH with Na metal(Mol.wt of ethanol =46 g/mol)?

Updated On: Apr 30, 2024
  • 2.3
  • 4.6
  • 1.15
  • 0.575
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The Correct Option is C

Solution and Explanation

The correct answer is option (C): 1.15
2C2H5OH +2Na →  2C2H5ONa +H2 
From the above reaction, we can see that 1 mole of H2 is produced by 2 moles of ethanol. At STP, 1 mole of gas occupies 22.4 L 
We have to produce 280ml of dihydrogen, the moles of ethanol required for the same are: 
2 moles of ethanol22.4L of H2= 2xmoles of ethanol0.28L of H2
x= 0.025 moles of ethanol.
The mass of ethanol required can be calculated by using the molar mass:
Molar mass of ethanol = 46.08 g/mol 
Mass of ethanol required = 0.025 moles x 46.08 g/mol
= 1.152 g
Therefore, the answer is 1.152 g
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Concepts Used:

Alcohols, Phenols, and Ethers

Alcohol is formed when a saturated carbon atom bonds to a hydroxyl (-OH) group. It is an organic compound that contains a hydroxyl functional group attached to a carbon atom.

Phenol is formed when the -OH group replaces the hydrogen atom in benzene. It is an organic compound in which a hydroxyl group directly attaches to an aromatic hydrocarbon.

Ether is formed when oxygen atom bonds to two alkyl or aryl groups. It is an organic compound that has an oxygen atom that is connected to two aryl and alkyl groups.

Read More: Alcohol, Phenol, and Ethers