There are 6 different letters in the word MONDAY.
(i) Number of 4-letter words that can be formed from the letters of the word MONDAY, without repetition of letters, is the number of permutations of 6 different objects taken 4 at a time, which is \(^6P_4\).
Thus, required number of words that can be formed using 4 letters at a time is
\(^6P_4=\frac{6!}{\left(6-4\right)!}=\frac{6!}{2!}\)
\(=\frac{6\times5\times4\times3\times2!}{2!}\)
\(=6\times5\times4\times3=360\)
(ii) Number of words that can be formed by using all the letters of the word MONDAY at a time is the number of permutations of 6 different objects taken 6 at a time, which is \(^6P_6=6!\)
Thus, required number of words that can be formed when all letters are used at a time = \(6! = 6\times5 \times 4 \times 3 \times 2 \times1 = 720\)
(iii) In the given word, there are 2 different vowels, which have to occupy the rightmost place of the words formed. This can be done only in 2 ways.
Since the letters cannot be repeated and the rightmost place is already occupied with a letter (which is a vowel), the remaining five places are to be filled by the remaining 5 letters. This can be done in 5! ways.
Thus, in this case, required number of words that can be formed is
\(5! \times 2 = 120 \times 2 = 240\)
The number of strictly increasing functions \(f\) from the set \(\{1, 2, 3, 4, 5, 6\}\) to the set \(\{1, 2, 3, ...., 9\}\) such that \(f(i)>i\) for \(1 \le i \le 6\), is equal to:
Find the mean deviation about the mean for the data 38, 70, 48, 40, 42, 55, 63, 46, 54, 44.
Permutation is the method or the act of arranging members of a set into an order or a sequence.
Combination is the method of forming subsets by selecting data from a larger set in a way that the selection order does not matter.