Question

How many two-digit numbers, with a non-zero digit in the units place, are there which are more than thrice the number formed by interchanging the positions of its digits?

• A. 5
• B. 6
• C. 8
• D. 7

Answer 1

The Correct Option is B

The correct answer is (B):
Let 'ab' be the two digit number. Where b ≠ 0.
On interchanging the digits, the new number will be ‘ba’
As per the condition 10a+b > 3×(10b + a)
7a > 29b
For b = 1, a = {5, 6, 7, 8, 9}
For b = 2, a = {9}
For b = 3, no value of 'a' is possible.
Hence, there are a total of 6 such numbers.