Step 1: Recall glucose structure.
Glucose (an aldohexose) has 6 carbons: one aldehyde group (–CHO) at C1, four secondary –OH groups (on C2, C3, C4, C5), and one terminal –CH$_2$OH (primary alcohol) at C6.
Step 2: Identify primary alcohol.
Only carbon 6 has –CH$_2$OH group, which is primary alcohol.
Step 3: Conclude.
There is exactly one primary alcoholic group in glucose.
Final Answer:
\[
\boxed{One}
\]
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