Question:

How many pairs of letters are there in the word ‘CHILDREN’ such that each pair has as many letters between them in the word ‘CHILDREN’ as they have in the English alphabet series?

Updated On: Oct 11, 2024
  • 2
  • 3
  • 4
  • 5
  • None of these
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The Correct Option is C

Solution and Explanation

This question actually expects the test takers to identify the number of pairs of letters in a word in which the number of letters between the first letter and the second letter of a pair must have the same number of letters as in English alphabet. For example, the positional difference between E and I in English alphabet is three (F,G and H are between them); the positional difference between E and I in the word CHILDREN is also three (L,D and R are between them). Hence, (E, I) is one such pair.
Similarly, in the word ‘CHILDREN’, the other pairs can be identified as below:
 • (H, I): The number of letter between ‘H’ and ‘I’ in English alphabet is zero as there is no letter between ‘H’ and ‘I’. Similarly in the word ‘CHILDREN’ the number of letter between ‘H’ and ‘I’ is also zero as there is no letter between ‘H’ and ‘I’.
(H, N): The number of letter between ‘H’ and ‘N’ in English alphabet is five as there are five letters between ‘H’ and ‘N’. Similarly in the word ‘CHILDREN’ the number of letter between ‘H’ and ‘N’ is also five as there are five letters between ‘H’ and ‘N’.
(I, N) : The number of letter between ‘I’ and ‘N’ in English alphabet is four as there are four letters between ‘I’ and ‘N’. Similarly in the word ‘CHILDREN’ the number of letter between ‘I’ and ‘N’ is also four as there are four letters between ‘I’ and ‘N’.
Therefore, there are four such pairs – (E, I), (H, I), (H, N) and (I, N). 
The correct answer is C.
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