To determine how FRIDAY is coded, we must first understand the logic used to encode MONDAY as NPOEBZ. Each letter in MONDAY is shifted one position forward in the alphabet:
M to N
O to P
N to O
D to E
A to B
Y to Z
Following the same pattern, we apply this encoding rule to FRIDAY by shifting each letter one position forward:
F to G
R to S
I to J
D to E
A to B
Y to Z
Thus, FRIDAY becomes GSJEBZ. Therefore, the correctly coded answer is GSJEBZ.
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Approach Solution -2
Given the word MONDAY is coded as NPOEBZ. Let's analyze the pattern letter by letter:
\[
\begin{array}{c|cccccc}
\text{Letter (Original)} & M & O & N & D & A & Y \\
\hline
\text{Letter (Coded)} & N & P & O & E & B & Z \\
\end{array}
\]
Comparing each letter's position in the alphabet (A=1, B=2, ..., Z=26):
\[
\begin{align*}
M(13) &\rightarrow N(14): +1 \\
O(15) &\rightarrow P(16): +1 \\
N(14) &\rightarrow O(15): +1 \\
D(4) &\rightarrow E(5): +1 \\
A(1) &\rightarrow B(2): +1 \\
Y(25) &\rightarrow Z(26): +1 \\
\end{align*}
\]
Pattern: Each letter is shifted forward by 1 in the alphabet.
Apply the same to FRIDAY:
\[
\begin{array}{c|cccccc}
\text{Letter (Original)} & F & R & I & D & A & Y \\
\hline
\text{Letter (Coded)} & G & S & J & E & B & Z \\
\end{array}
\]
Answer:GSJEBZ