How many moles of ethene are required to prepare 6 g of ethane by hydrogenation process?
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In the hydrogenation reaction, 1 mole of ethene produces 1 mole of ethane. Use the molar mass to determine the number of moles needed for a specific mass.
Step 1: Understanding the hydrogenation process.
In the hydrogenation process, ethene (C\(_2\)H\(_4\)) reacts with hydrogen (H\(_2\)) to form ethane (C\(_2\)H\(_6\)). The balanced equation for the reaction is:
\[
\text{C}_2\text{H}_4 + \text{H}_2 \rightarrow \text{C}_2\text{H}_6
\]
This indicates that 1 mole of ethene reacts with 1 mole of hydrogen to form 1 mole of ethane. Step 2: Calculation.
The molar mass of ethane (C\(_2\)H\(_6\)) is 30 g/mol. To prepare 6 g of ethane, we need:
\[
\frac{6 \, \text{g}}{30 \, \text{g/mol}} = 0.2 \, \text{moles of ethane}
\]
Since the molar ratio of ethene to ethane is 1:1, we need 0.2 moles of ethene. Step 3: Conclusion.
The correct answer is (A) 0.2 mole.
