Question

How many mole of electrons are required for the reduction of 1 mole of Cr³⁺ to Cr_(s)?

• A. 1
• B. 6.022 x 10²³
• C. 3
• D. 6

Answer 1

The Correct Option is C

The balanced reduction half-reaction for the reduction of Cr³⁺ to Cr_(s) can be represented as Cr³⁺_(aq) + 3e^- \(\rightarrow\) Cr_(s)
From the balanced equation, we can see that 3 moles of electrons (3e^-) are required to reduce 1 mole of Cr³⁺ to Cr_(s).
Therefore, the correct answer is 3.