Radius of the hemispherical bowl, r = \(\frac{10.5}{2}\) cm = 5.25 cm
Volume of the hemispherical bowl =\(\frac{ 2}{3}\pi\) r3
= \(\frac{2}{3}\) × \(\frac{22}{7}\) × 5.25 cm × 5.25 cm × 5.25 cm
= 303.1875 cm3
\(= \frac{303.1875 }{1000}\) (1000cm3 = 1L)
= 0.3031875 liters
= 0.303 liters
Therefore, the volume of the hemispherical bowl is 0.303 liter.
List-I | List-II | ||
(A) | Volume of cone | (I) | \(\frac{1}{3}\pi h(r_1^2+r_2^2+r_1r_2)\) |
(B) | Volume of sphere | (II) | \(\frac{1}{3}\pi r^2h\) |
(C) | Volume of Frustum | (III) | \(\pi r^2h\) |
(D) | Volume of cylinder | (IV) | \(\frac{4}{3}\pi r^3\) |
In Fig. 9.26, A, B, C and D are four points on a circle. AC and BD intersect at a point E such that ∠ BEC = 130° and ∠ ECD = 20°. Find ∠ BAC.