From previous solution, at meeting point:
- P covered distance = \( vt = v \times 2 = 2v \)
- This distance was said to be \( \frac{1}{6} \) of total distance:
\[
2v = \frac{1}{6} D D = 12v
\]
P’s speed = \( v \), total distance = \( 12v \)
So total time to reach B:
\[
\frac{12v}{v} = \boxed{12 \text{ hours}}
\]