Question:
How many g of dibasic acid (mol. wt. 200) should be present in 100 mL of the aqueous solution to give 0.1 normality ?
How many g of dibasic acid (mol. wt. 200) should be present in 100 mL of the aqueous solution to give 0.1 normality ?
Updated On: May 5, 2024
- 1 g
- 2 g
- 10 g
- 20 g
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The Correct Option is A
Solution and Explanation
Equivalent weight of dibasic acid
$=\frac{ mol , \text { wt. }}{2}=\frac{200}{2}=100$
Strength $=0.1 \,N , m =?, V =100\, ml .$
From, $m =\frac{ E V N }{1000}$
$=\frac{100 \times 100 \times 0.1}{1000}=1\, g$
$=\frac{ mol , \text { wt. }}{2}=\frac{200}{2}=100$
Strength $=0.1 \,N , m =?, V =100\, ml .$
From, $m =\frac{ E V N }{1000}$
$=\frac{100 \times 100 \times 0.1}{1000}=1\, g$
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.