Question:
Henry's law constants for aqueous solution of $CO , O _{2}, CO _{2}$ and $C _{2} H _{2}$ gases are respectively at $25^{\circ} C$ as $58 \times 10^{3}, 43 \times 10^{3}, 1.61 \times 10^{3}$ and $1.34 \times 10^{3}$. The solubility of these gases decreases in the order
Henry's law constants for aqueous solution of $CO , O _{2}, CO _{2}$ and $C _{2} H _{2}$ gases are respectively at $25^{\circ} C$ as $58 \times 10^{3}, 43 \times 10^{3}, 1.61 \times 10^{3}$ and $1.34 \times 10^{3}$. The solubility of these gases decreases in the order
Updated On: Jun 23, 2023
- $ CO>O_{2}>CO_{2}>C_{2}H_{2}$
- $O_{2}>CO_{2}>CO>C_{2}H_{2}$
- $C_{2}H_{2}>CO_{2}>O_{2}>CO $
- $O_{2}>CO_{2}>C_{2}H_{2}>CO $
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
$p=K_{H} X$; Higher the value of $K_{H}$ at a given pressure, the lower is the solubility of the gas in the liquid.
Therefore, the solubility of the given gases decreases in the order
$C _{2} H _{2}> CO _{2}> O _{2}> CO$
Therefore, the solubility of the given gases decreases in the order
$C _{2} H _{2}> CO _{2}> O _{2}> CO$
Was this answer helpful?
0
0
Top Questions on Solutions
- Which of the following compound can give positive iodoform test when treated with aqueous KOH solution followed by potassium hypoiodite.
- A molecule X associates in a given solvent as per the following equation:
X ⇌ (X)n
For a given concentration of X, the van’t Hoff factor was found to be 0.80 and the
fraction of associated molecules was 0.3. The correct value of ‘n’ is: - Arrange the following compounds in increasing order of their solubilities in chloroform:
NaCl, CH3OH, cyclohexane, CH3CN - The amount of glucose required to prepare 250 mL of \( \frac{M}{20} \) aqueous solution is:
(Molar mass of glucose: 180 g mol-1) - Mass of ethylene glycol (antifreeze) to be added to 18.6 kg of water to protect the freezing point at $-24^\circ C$ is ____ kg (Molar mass in g mol$^{-1}$ for ethylene glycol = 62, $K_f$ of water = 1.86 K kg mol$^{-1}$).
View More Questions
Questions Asked in AMUEEE exam
- The ratio of the half-life time $ (t_{1/2}) $ , to the three quarter life-time, $ (t_{3/4}) $ , for a reaction that is second order
- AMUEEE - 2018
- Order of Reaction
- $ 0.002\, M $ solution of a weak acid has an equivalent conductance $ (\wedge) 60\, ohm^{-1}\, cm^{2}\, eq^{-1} $ . What will be the $ pH $ ? (Given : $ \wedge = 400 \, ohm^{-1} \, cm^{2} \, eq^{-1} $ ]
- AMUEEE - 2018
- Electrochemistry
- The electrode potential, $ E^{\circ} $ , for the reduction of $ MnO^{-}_{4} $ to $ Mn^{2+} $ in acidic medium is $ +1.51\, V $ . Which of the following metal(s) will be oxidised? The reduction reactions and standard electrode potentials for $ Zn^{2+}, Ag^{+} $ , and $ Au^{+} $ are given as $ Zn^{2+} (aq) +2e \to Zn(s), E^{\circ} = -0.762\, V $ $ Ag+ (aq) +e {\rightleftharpoons} Ag (s), E^{\circ}=+0.80 \,V $ $ Au^{+} (aq) +e {\rightleftharpoons} Au(s), E^{\circ}+1.69\,V $
- AMUEEE - 2018
- Electrochemistry
- Three particles, two with masses $ m $ and one with mass $ M $ , might be arranged in any of the four configurations shown below. Rank the configurations according to the magnitude of the gravitational force on $ M $ , least to greatest
- AMUEEE - 2018
- Gravitation
- The $ EAN $ value $ y \left[Ti\left(\sigma-C_{6}H_{5}\right)_{2}\left(\pi-C_{5}H_{5}\right)_{2}\right]^{0} $ is
- AMUEEE - 2018
- coordination compounds
View More Questions
Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.