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hbr reacts with ch 2 ch och 3 under anhydrous cond
Question:
HBr reacts with
$CH_{2} =CH-OCH_{3}$
under anhydrous conditions at room temperature to give:
AIEEE - 2008
AIEEE
Updated On:
Jul 27, 2022
$CH_{3} CHO and CH_{3} Br$
$BrCH_{2} CHO and CH_{3}OH$
$BrCH_{2}- CH_{2}-OCH_{3}$
$H_{3}C-CHBr-OCH_{3}$
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The Correct Option is
D
Solution and Explanation
First protonation occurs, two possible intermediates are (-1effect destabilizes carbocation) (+M effect stabilizes carbocation) II, is more favourable Hence,
$Br^{\Theta}$
attacks, and product is
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