Question:

HBr reacts with $CH_{2} =CH-OCH_{3}$ under anhydrous conditions at room temperature to give:

Updated On: Jul 27, 2022
  • $CH_{3} CHO and CH_{3} Br$
  • $BrCH_{2} CHO and CH_{3}OH$
  • $BrCH_{2}- CH_{2}-OCH_{3}$
  • $H_{3}C-CHBr-OCH_{3}$
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The Correct Option is D

Solution and Explanation

First protonation occurs, two possible intermediates are (-1effect destabilizes carbocation) (+M effect stabilizes carbocation) II, is more favourable Hence, $Br^{\Theta}$ attacks, and product is
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