Question:
Given that, for the reaction,
\(\frac 12H_2+\frac 12Cl_2→HCl\)
△Hf (HCI) = -93 kJ/mol, B.E(H2) = 434 kJ/mol, B.E(Cl2) = 242 kJ/mol
The bond dissociation energy of HCl is
Given that, for the reaction,
\(\frac 12H_2+\frac 12Cl_2→HCl\)
△Hf (HCI) = -93 kJ/mol, B.E(H2) = 434 kJ/mol, B.E(Cl2) = 242 kJ/mol
The bond dissociation energy of HCl is
\(\frac 12H_2+\frac 12Cl_2→HCl\)
△Hf (HCI) = -93 kJ/mol, B.E(H2) = 434 kJ/mol, B.E(Cl2) = 242 kJ/mol
The bond dissociation energy of HCl is
Updated On: Oct 9, 2024
- 232 kJ/mol
- 331 kJ/mol
- 431 kJ/mol
- 530 kJ/mol
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The Correct Option is C
Solution and Explanation
The correct option is (C): 431 kJ/mol.
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