Step 1: Understanding vertical curves.
In road design, vertical curves are used to provide smooth transitions between different road grades. There are two types of vertical curves:
- Sag curve: A concave curve where the grade changes from a negative to a less negative value or from a positive to a less positive value.
- Crest curve: A convex curve where the grade changes from a positive to a less positive value or from a negative to a less negative value.
Step 2: Evaluating the statements.
- Statement 1: \( +G_1 \) followed by \( +G_2 \) results in a sag vertical curve.
This is true. In a sag vertical curve, both grades are positive but the second grade \( G_2 \) is smaller than the first \( G_1 \), making the curve concave.
- Statement 2: \( -G_1 \) followed by \( -G_2 \) results in a sag vertical curve.
This is false. If both \( G_1 \) and \( G_2 \) are negative, it means the slope is descending throughout, and there's no change to create a curve. This would be a straight, descending path.
- Statement 3: \( +G_1 \) followed by \( -G_2 \) results in a crest vertical curve.
This is true. If \( G_1 \) is positive and \( G_2 \) is negative, the curve transitions from an upward slope to a downward slope, making it a crest curve.
Thus, the correct answer is (A): Statement 1 and Statement 3 are correct; Statement 2 is wrong.
\[
\boxed{\text{The correct option is (A).}}
\]
Two soils of permeabilities \( k_1 \) and \( k_2 \) are placed in a horizontal flow apparatus, as shown in the figure. For Soil 1, \( L_1 = 50 \, {cm} \), and \( k_1 = 0.055 \, {cm/s} \); for Soil 2, \( L_2 = 30 \, {cm} \), and \( k_2 = 0.035 \, {cm/s} \). The cross-sectional area of the horizontal pipe is 100 cm², and the head difference (\( \Delta h \)) is 150 cm. The discharge (in cm³/s) through the soils is ........ (rounded off to 2 decimal places).
Consider the beam ACDEB given in the figure. Which of the following statements is/are correct:
The figures, I, II, and III are parts of a sequence. Which one of the following options comes next in the sequence as IV?
For the beam and loading shown in the figure, the second derivative of the deflection curve of the beam at the mid-point of AC is given by \( \frac{\alpha M_0}{8EI} \). The value of \( \alpha \) is ........ (rounded off to the nearest integer).