To solve this problem, we need to analyze the two statements given in the context of circle geometry.
If two chords \(XY\) and \(ZT\) of a circle intersect internally at point \(P\), then PX \cdot PY = PZ \cdot PT.
This statement corresponds to the properties of intersecting chords in circle geometry. When two chords intersect inside a circle, the product of the lengths of the segments of one chord is equal to the product of the segments of the other chord. This is a well-known theorem in circle geometry, often referred to as the chord intersection theorem. Therefore, Statement I is true.
If two chords \(XY\) and \(ZT\) of a circle intersect internally at point \(P\), then triangles \(PXZ\) and \(PTY\) are similar.
To verify this, note that when two chords intersect, the opposite angles formed are equal (vertically opposite angles). Thus, \(\angle XPZ = \angle YPT\). Also, \(\angle PZX = \angle PTY\) as they subtend the same arcs on the circle. Hence, by AA (Angle-Angle) similarity criterion, triangles \(PXZ\) and \(PTY\) are similar. Therefore, Statement II is also true.
Both Statement I and Statement II are true. The correct answer is Both Statement I and Statement II are true.