Question:
Given below are two statements:
Statement-I: The tangential component of the electric field intensity is continuous across an interface between two general materials, regardless of charge densities on the surface.
Statement-II The tangential component of the electric flux density is discontinuous across the interface. The discontinuity is equal to the ratio between the permittivities of the materials.
In the light of the above statements, choose the correct answer from the options given below.
Given below are two statements:
Statement-I: The tangential component of the electric field intensity is continuous across an interface between two general materials, regardless of charge densities on the surface.
Statement-II The tangential component of the electric flux density is discontinuous across the interface. The discontinuity is equal to the ratio between the permittivities of the materials.
In the light of the above statements, choose the correct answer from the options given below.
Statement-I: The tangential component of the electric field intensity is continuous across an interface between two general materials, regardless of charge densities on the surface.
Statement-II The tangential component of the electric flux density is discontinuous across the interface. The discontinuity is equal to the ratio between the permittivities of the materials.
In the light of the above statements, choose the correct answer from the options given below.
Updated On: Mar 21, 2024
- Both Statement-I and Statement-ll are true
- Both Statement-I and Statement-ll are false
- Statement-I is true but Statement-II is false
- Statement-I is false but Statement-II is true
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The Correct answer is option (A) : Both Statement-I and Statement-ll are true
Was this answer helpful?
0
0
Top Questions on Electric Flux Density
- An electric field, \(\vec{E} = \frac{2\hat{i} + 6\hat{j} + 8\hat{k}}{\sqrt{6}}\) passes through the surface of \(4 \, \text{m}^2\) area having unit vector \(\hat{n} = \frac{2\hat{i} + \hat{j} + \hat{k}}{\sqrt{6}}\). The electric flux for that surface is _________ \( \text{V m} \).
- JEE Main - 2024
- Physics
- Electric Flux Density
- An electric field is given by \( (6\hat{i} + 5\hat{j} + 3\hat{k}) \, \text{N/C} \). The electric flux through a surface area \( 30\hat{i} \, \text{m}^2 \) lying in the YZ-plane (in SI units) is:
- JEE Main - 2024
- Physics
- Electric Flux Density
- In a Bainbridge mass spectrograph singly ionized atoms of a Neon-20 pass into the deflection chamber with the velocity of 105 m/sec. If they are deflected by a magnetic field of flux density 0.08 tesla, then the path radius of Neon-20 ion is ____
- SRMJEEE - 2018
- Physics
- Electric Flux Density
Questions Asked in CUET PG exam
- Find out the degree of the differential equation \(\frac {d^2t}{ds^2}+(\frac {dt}{ds})^2+2t=0\)
- CUET (PG) - 2023
- Differential Equations
- The surface area of the sphere x2 + y2 + z2 = 9 lying inside the cylinder x2 + y2 = 3y is
- CUET (PG) - 2023
- Surface Area of Cube, Cuboid and Cylinder
- The Ombudsman in a newspaper organisation represents the point of view of the ___.
- CUET (PG) - 2023
- Journalism
- The orthogonal trajectories of the family of curves y = \(ax^3\) is
- The minimum distance of the point (3, 4, 12) from the sphere x2 + y2 + z2 = 1 is
- CUET (PG) - 2023
- Coordinate Geometry
View More Questions