Given below are two statements.
Statement I: The compound
(A) is optically active.
Statement II:
is a mirror image of the above compound A.
In the light of the above statement, choose the most appropriate answer from the options given below.
Statement I: The compound
(A) is optically active.
Statement II:
is a mirror image of the above compound A.
In the light of the above statement, choose the most appropriate answer from the options given below.
- Both Statement I and Statement II are correct.
- Both Statement I and Statement II are incorrect.
- Statement I is correct but Statement II is incorrect.
- Statement I is incorrect but Statement II is correct.
The Correct Option is C
Solution and Explanation
The given question involves the concepts of optical activity and chirality in organic chemistry.
- Statement I Analysis:
- The compound shown (Compound A) is a type of organic molecule with a chiral center. A chiral center is typically a carbon atom bonded to four different groups.
- Optical activity arises from such chiral centers because they allow the molecule to rotate plane-polarized light. If a compound can do this, it is considered optically active.
- In the structure of the compound, the presence of stereochemistry (the depiction of the spatial arrangement with bonds shown as wedges and dashes) indicates chirality, making the compound optically active.
- Statement II Analysis:
- The second structure is provided as a potential mirror image of Compound A.
- A true mirror image of a chiral compound would be its enantiomer, which would also be chiral but with an opposite configuration (i.e., if the original compound is R, the mirror image should be S, and vice versa).
- By visual inspection, the given mirror image does not change the configuration correctly, or if it does not maintain the enantiomeric nature, it fails to be a true mirror image.
Based on the analyses, the correct option is: Statement I is correct but Statement II is incorrect.
Top Questions on Chemical bonding and molecular structure
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are :
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- The wave numbers of three spectral lines of hydrogen atom are considered. Identify the set of spectral lines belonging to the {Balmer series. (\(R\) = Rydberg constant)}
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- Consider the reaction: \[ \text{Ph–CH=CH}_2 \xrightarrow[\text{peroxide}]{\text{HBr}} \text{Product} \] Which of the following statements are correct?
[A.] The reaction proceeds through a more stable radical intermediate.
[B.] The role of peroxide is to generate \(\mathrm{H^\bullet}\) radical.
[C.] During this reaction, benzene is formed as a byproduct.
[D.] \(1\)-Bromo-\(2\)-phenylethane is formed as a minor product.
[E.] The same reaction in absence of peroxide proceeds via a carbocation intermediate. Choose the correct answer.- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is :
- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
- Given below are two statements :
Statement I : The correct order in terms of bond dissociation enthalpy is \( Cl_2>Br_2>F_2>I_2 \).
Statement II : The correct trend in the covalent character of the metal halides is \( SnCl_2>SnCl_4 \), \( PbCl_2>PbCl_4 \) and \( UF_4>UF_6 \).
In the light of the above statements, choose the correct answer from the options given below :- JEE Main - 2026
- Chemistry
- Chemical bonding and molecular structure
Questions Asked in JEE Main exam
Which one of the following graphs accurately represents the plot of partial pressure of CS₂ vs its mole fraction in a mixture of acetone and CS₂ at constant temperature?
- JEE Main - 2026
- Organic Chemistry
- Let \( ABC \) be an equilateral triangle with orthocenter at the origin and the side \( BC \) lying on the line \( x+2\sqrt{2}\,y=4 \). If the coordinates of the vertex \( A \) are \( (\alpha,\beta) \), then the greatest integer less than or equal to \( |\alpha+\sqrt{2}\beta| \) is:
- JEE Main - 2026
- Coordinate Geometry
- Three charges $+2q$, $+3q$ and $-4q$ are situated at $(0,-3a)$, $(2a,0)$ and $(-2a,0)$ respectively in the $x$-$y$ plane. The resultant dipole moment about origin is ___.
- JEE Main - 2026
- Electromagnetic waves
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.- JEE Main - 2026
- Complex Numbers and Quadratic Equations
- The work functions of two metals ($M_A$ and $M_B$) are in the 1 : 2 ratio. When these metals are exposed to photons of energy 6 eV, the kinetic energy of liberated electrons of $M_A$ : $M_B$ is in the ratio of 2.642 : 1. The work functions (in eV) of $M_A$ and $M_B$ are respectively.
- JEE Main - 2026
- Dual nature of matter
Concepts Used:
Chemical Bonding and Molecular Structure
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
Types of Chemical Bonds:
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.
- Ionic Bonds - Ionic bonding is a type of chemical bonding which involves a transfer of electrons from one atom or molecule to another.
- Covalent Bonds - Compounds that contain carbon commonly exhibit this type of chemical bonding.
- Hydrogen Bonds - It is a type of polar covalent bonding between oxygen and hydrogen wherein the hydrogen develops a partial positive charge
- Polar Bonds - In Polar Covalent chemical bonding, electrons are shared unequally since the more electronegative atom pulls the electron pair closer to itself and away from the less electronegative atom.
Factors Affecting Bond Enthalpy in Chemical Bonding:
- Size of the Atom
- Multiplicity of Bonds
- Number of Lone Pair of Electrons Present
- Bond Angle