Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): Experimental reaction of \(CH_3Cl\) with aniline and anhydrous \(AlCl_3\) does not give o and p-methylaniline.
Reason (R): The \(–NH_2\)group of aniline becomes deactivating because of salt formation with anhydrous \(AlCl_3\) and hence yields m-methyl aniline as the product.
In the light of the above statements, choose the most appropriate answer from the options given below :
Assertion (A): Experimental reaction of \(CH_3Cl\) with aniline and anhydrous \(AlCl_3\) does not give o and p-methylaniline.
Reason (R): The \(–NH_2\)group of aniline becomes deactivating because of salt formation with anhydrous \(AlCl_3\) and hence yields m-methyl aniline as the product.
In the light of the above statements, choose the most appropriate answer from the options given below :
- Both (A) and (R) are true and (R) is the correct explanation of (A).
- Both (A) and (R) are true but (R) is not the correct explanation of (A).
- (A) is true, but (R) is false.
- (A) is false, but (R) is true.
The Correct Option is C
Solution and Explanation
Aniline does not undergo Friedel Craft reaction because the reagent \(AlCl_3\) being electron deficient acts as a Lewis acid.
So, the correct option is (C): (A) is true, but (R) is false.
Top Questions on Amines
The correct order of basicity for the following molecules is:
- Identify correct statements: (A) Primary amines do not give diazonium salts when treated with \({NaNO}_2\) in acidic condition.
(B) Aliphatic and aromatic primary amines on heating with \({CHCl}_3\) and ethanolic \({KOH}\) form carbylamines.
(C) Secondary and tertiary amines also give carbylamine test.
(D) Benzenesulfonyl chloride is known as Hinsberg’s reagent.
(E) Tertiary amines react with benzenesulfonyl chloride very easily.
Choose the correct answer from the options given below: The descending order of basicity of following amines is :
Choose the correct answer from the options given below :Which of the following amine(s) show(s) positive carbamylamine test?
- An amine 'X' reacts with Hinsberg reagent and the product obtained is soluble in alkali. The amine 'X' is:
Questions Asked in JEE Main exam
- Total number of sigma (\( \sigma \)) and pi (\( \pi \)) bonds respectively present in hex-1-en-4-yne are:
- JEE Main - 2025
- Organic Chemistry
- Identify the homoleptic complexes with odd number of d-electrons in the central metal:
(A) [FeO4]2− (B) [Fe(CN)6]3−
(C) [Fe(CN)5NO]2− (D) [CoCl4]2−
(E) [Co(H2O)3F3]
Choose the correct answer from the options given below :
- JEE Main - 2025
- Coordination chemistry
O\(_2\) gas will be evolved as a product of electrolysis of:
(A) an aqueous solution of AgNO3 using silver electrodes.
(B) an aqueous solution of AgNO3 using platinum electrodes.
(C) a dilute solution of H2SO4 using platinum electrodes.
(D) a high concentration solution of H2SO4 using platinum electrodes.
Choose the correct answer from the options given below :- JEE Main - 2025
- Electrolysis
- 0.1 M solution of KI reacts with excess of \( \text{H}_2\text{SO}_4 \) and KIO\(_3\), according to the equation: \[ 5I^- + 6H^+ \rightarrow 3I_2 + 3H_2O \]Identify the correct statements:
- (A) 200 mL KI solution reacts with 0.004 mol of KIO3
- (B) 200 mL KI solution reacts with 0.006 mol of H2SO4
- (3) 0.5 L KI solution produced 0.005 mol of I2
- (4) Equivalent weight of KIO3 is equal to Molecular weight / 5
- JEE Main - 2025
- Solutions
- Given below are two statements:
Statement (I): On nitration of m-xylene with \( \text{HNO}_3 \), \( \text{H}_2\text{SO}_4 \), followed by oxidation, 4-nitrobenzene-1, 3-dicarboxylic acid is obtained as the major product.
Statement (II): CH\(_3\) group is o/p-directing while NO\(_2\) group is m-directing group.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Organic Reactions
Concepts Used:
Amines - Chemical Properties
There are many chemical properties of amines.
The primary and secondary amines, including several amine derivatives, have a direct impact on their properties due to the presence of hydrogen bonding. The compounds containing phosphorus have a lower boiling point and the compounds containing amines and alcohol have a higher boiling point. The structure of alkanols is immensely similar to that of amine except the presence of the hydroxyl group. In such a case, oxygen has a higher electronegativity than that of nitrogen, so alkanol compounds are more acidic in nature in comparison to the amines.
On account of the ability to form hydrogen bonds, the amines have tendencies of high solubility in water. The amine molecules such as Ethyl, diethyl, triethyl, and Methyl are gaseous in nature. Whereas, higher weight amines have a solid structure and alkyl amines have a liquid structure. There is an ammonia smell to gaseous amines and a fishy smell to liquid amines. The solubility of amines entirely depends upon the number of carbon atoms in the molecule.