In a graph where the velocity is a function of \( t^2 \), the graph should show a curve that increases non-linearly with time, indicating that the rate of change of velocity increases over time. In this case, the graph labeled A shows the characteristic curve of a velocity-time plot where the velocity is increasing with time in such a way that it is related to \( t^2 \). The relationship is quadratic, which fits the description of a function of \( t^2 \). Thus, graph A is the correct one for this scenario
The correct option is (A) :
If the velocity of a particle is a function of time squared, i.e.,
$v = k t^2$ (where $k$ is a constant),
then the velocity-time graph will be a parabola opening upwards if $k > 0$.
Among the given graphs, the one that curves upwards in a parabolic shape represents a velocity that increases with the square of time.
Therefore, the correct graph is the one showing a parabolic curve.
The motion of an airplane is represented by the velocity-time graph as shown below. The distance covered by the airplane in the first 30.5 seconds is km.
A particle is moving along x-axis with its position ($ x $) varying with time ($ t $) as:
$ x = \alpha t^4 + \beta t^2 + \gamma t + \delta. $
The ratio of its initial velocity to its initial acceleration, respectively, is: