- Let the total work required to finish be W.
- If Ginny takes 3 hours to finish the work, Ginny’s rate of work is:
\[ \text{Ginny's rate} = \frac{W}{3} \text{ work per hour} \]
- Sunny works half as fast as Ginny, so Sunny’s rate of work is:
\[ \text{Sunny's rate} = \frac{W}{6} \text{ work per hour} \]
- Together, their combined rate of work is:
\[ \text{Combined rate} = \frac{W}{3} + \frac{W}{6} \]
Taking the LCM of 3 and 6:
\[ \text{Combined rate} = \frac{2W}{6} + \frac{W}{6} = \frac{3W}{6} = \frac{W}{2} \]
- To complete work twice as large (2W), the total time required is:
\[ \text{Time} = \frac{2W}{\frac{W}{2}} = 4 \text{ hours} \]
Conclusion: Sunny and Ginny together will take 4 hours to finish the work twice as large.
The correct answer is (b) 4 hours.