Question:

Geeta is twice the present age of Seema. If age of Seema is 20 years now, how many years ago Geeta was times Seema’s age?

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Set up a system of equations based on the relationship between the ages at a specific point in time.
Updated On: Aug 18, 2025
  • 10
  • 8
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  • 9
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The Correct Option is A

Solution and Explanation

Let the present age of Seema be \( S = 20 \) years. Geeta's present age is twice that of Seema's, i.e., \( G = 2 \times 20 = 40 \) years. Let the number of years ago be \( x \). At that time, Geeta's age was \( 40 - x \) and Seema's age was \( 20 - x \). According to the question, Geeta was twice Seema's age, so we have the equation: \[ 40 - x = 2(20 - x) \] Solving for \( x \): \[ 40 - x = 40 - 2x
x = 10 \]
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