Question

Gas X is obtained in Deacon's process. X on reacting with iodine and water gives:

• A. HIO$_4$
• B. HIO$_2$
• C. HIO
• D. HIO$_3$

Hint:

Key points to remember: \begin{itemize} \item Deacon's process produces chlorine gas \item Chlorine is a strong oxidizing agent that converts iodine to iodic acid (HIO$_3$) \item The oxidation state of iodine in HIO$_3$ is +5 \end{itemize}

Answer 1

The Correct Option is D

Step 1: Identify Gas X from Deacon's process
In Deacon's process, chlorine gas (Cl$_2$) is produced by catalytic oxidation of hydrogen chloride: \[ 4HCl + O_2 \rightarrow 2Cl_2 + 2H_2O \] Thus, X = Cl$_2$ Step 2: Reaction with iodine and water
Chlorine reacts with iodine and water to form iodic acid: \[ 5Cl_2 + I_2 + 6H_2O \rightarrow 2HIO_3 + 10HCl \]