\( \text{MnO}_2 + 2\text{KOH} + \text{KNO}_3 \rightarrow \text{K}_2\text{MnO}_4 + \text{KNO}_2 + \text{H}_2\text{O} \)
X is \( \text{K}_2\text{MnO}_4 \) (potassium manganate), which is dark green.
2. Disproportionation of X in acidic solution:\( 3\text{K}_2\text{MnO}_4 + 4\text{HCl} \rightarrow 2\text{KMnO}_4 + \text{MnO}_2 + 2\text{H}_2\text{O} + 4\text{KCl} \)
Y is \( \text{KMnO}_4 \) (potassium permanganate), which is purple.
Z is \( \text{MnO}_2 \) (manganese dioxide), which is brown.
3. Oxidation states and electronic configurations:In \( \text{KMnO}_4 \) (Y), Mn is in +7 oxidation state. Mn\(^{7+}\) has a configuration of [Ar] 3d\(^0\), so it has 0 unpaired electrons.
In \( \text{MnO}_2 \) (Z), Mn is in +4 oxidation state. Mn\(^{4+}\) has a configuration of [Ar] 3d\(^3\), so it has 3 unpaired electrons.
4. Spin-only magnetic moment:Spin-only magnetic moment (\( \mu \)) = \( \sqrt{n(n+2)} \) BM, where \( n \) is the number of unpaired electrons.
For Mn\(^{7+}\) (Y), \( n = 0 \), \( \mu = \sqrt{0(0+2)} = 0 \) BM.
For Mn\(^{4+}\) (Z), \( n = 3 \), \( \mu = \sqrt{3(3+2)} = \sqrt{15} \approx 3.87 \) BM.
5. Sum of magnetic moments:Sum = 0 + 3.87 = 3.87 BM
Therefore, the sum of spin-only magnetic moment values of 'Y' and 'Z' is 3.87.
Final Answer:Two statements are given below
Statement I: Benzanamine can be prepared from phthalimide.
Statement II: Benzanamine is less basic than phenyl methanamine.
What are X and Z in the following reaction sequence?
What is Y in the following reaction sequence?
Observe the following set of reactions:
Correct statement regarding Y and B is:
What is X in the following reaction?