The given data can be represented as follows.
f + g + d =10 (given)
g + e = b (given)
Since f + g + d = 10, g = 7 = 2g – 1
Therefore, 2g = 8 ∴ f = 4
Thus, g = 4, c = 8, a = 7 and f + d = 6
b + e = 39 – (G + c) = 14 therefore g + 2e = 14
Hence, e = 5 and b = 9
Since, L is maximum we get the following cases.
Case (i)
G = 17 K = 20 L = 21 d = 2 f = 4
Case (ii)
G = 17 K = 19 L = 22 d = 1 f = 5
Case (iii)
G = 17 K = 18 L = 23 d = 0 f = 6
G and L but not K = f = 4.
Ans : 4
The correct answer is (D):
The given condition is possible in case (ii).
Hence, the number of students enrolled in L = 22.
Ans : 22
From g = 4, one person moves to f, one person to d and two persons to e.
Then the value of G and K = d + g = 2.
Ans : 2
The correct answer is (A):
From the above G and L = f = 6.
Ans : 6