In the given figure, we have a triangle ABC. The angle at vertex A is given as \( 50^\circ \). The exterior angle at vertex C, \( \angle ACD \), is given as \( 120^\circ \). We need to find the value of the interior angle at vertex B, which is labeled as \( x \).
According to the Exterior Angle Theorem, the exterior angle of a triangle is equal to the sum of the two opposite interior angles. In triangle ABC, the exterior angle at C (\( \angle ACD \)) is equal to the sum of the interior angles at A (\( \angle BAC \)) and B (\( \angle ABC \)).
So, we have:
$$ \angle ACD = \angle BAC + \angle ABC $$
Substituting the given values:
$$ 120^\circ = 50^\circ + x $$
To find the value of \( x \), we can rearrange the equation:
$$ x = 120^\circ - 50^\circ $$
$$ x = 70^\circ $$
Therefore, the value of \( x \) is \( 70^\circ \).