The equation of the family of the ellipses having foci on the y-axis and the centre at origin is as follows:
\(\frac{x2}{b2}+\frac{y^2}{a^2}=1...(1)\)
Differentiating equation(1)with respect to x,we get:
\(\frac{2x}{b^2}+\frac{2yy}{b^2}=0\)
\(⇒\frac{x}{b^2}+\frac{yy}{a^2}=0...(2)\)
Again, differentiating with respect to we get:
\(\frac{1}{b^2}+\frac{y.y+y.y}{a^2}=0\)
\(⇒\frac{1}{b^2}+\frac{1}{a^2}(y^2+yy)=0\)
\(⇒\frac{1}{b^2}=-\frac{1}{a^2}(y^2+yy)\)
Substituting this values in equation(2),we get:
\(x[-\frac{1}{a^2}((y)2+yy)]+\frac{yy}{a^2}=0\)
\(⇒-x(y)^2-xyy+yy=0\)
\(⇒xyy+x(y)2-yy=0\)
This is the required differential equation.
Let $ y(x) $ be the solution of the differential equation $$ x^2 \frac{dy}{dx} + xy = x^2 + y^2, \quad x > \frac{1}{e}, $$ satisfying $ y(1) = 0 $. Then the value of $ 2 \cdot \frac{(y(e))^2}{y(e^2)} $ is ________.
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
A school is organizing a debate competition with participants as speakers and judges. $ S = \{S_1, S_2, S_3, S_4\} $ where $ S = \{S_1, S_2, S_3, S_4\} $ represents the set of speakers. The judges are represented by the set: $ J = \{J_1, J_2, J_3\} $ where $ J = \{J_1, J_2, J_3\} $ represents the set of judges. Each speaker can be assigned only one judge. Let $ R $ be a relation from set $ S $ to $ J $ defined as: $ R = \{(x, y) : \text{speaker } x \text{ is judged by judge } y, x \in S, y \in J\} $.
A relation between involved variables, which satisfy the given differential equation is called its solution. The solution which contains as many arbitrary constants as the order of the differential equation is called the general solution and the solution free from arbitrary constants is called particular solution.
Read More: Formation of a Differential Equation