Question:

Four identical thin rods each of mass M and length $l$, form a square frame. Moment of inertia of this frame about an axis through the centre of the square and perpendicular to its plane is

Updated On: May 25, 2022
  • $\frac{2}{3}Ml^2$
  • $\frac{13}{3}Ml^2$
  • $\frac{1}{3}Ml^2$
  • $\frac{4}{3}Ml^2$
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The Correct Option is D

Solution and Explanation

$I =4 \times\left[\frac{ M \ell^{2}}{12}+ M \left(\frac{\ell}{2}\right)^{2}\right]$
the parallel axis theorem $=\frac{4}{3} M \ell^{2}$
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