Step 1: We are given the forward current \( I_F = 75 mA \) and the forward voltage drop \( V_F = 0.6 V \). We have to find the forward resistance \( R_F \).
Step 2: Using Ohm's Law, which states \( V = IR \), the forward resistance \( R_F \) can be calculated as:
\[
R_F = \frac{V_F}{I_F} = \frac{0.6}{75 \times 10^{-3}} = \frac{0.6}{0.075} = 8 \, \Omega
\]