Question

Forestland is a planet inhabited by different kinds of creatures. Among other creatures, it is populated by animals all of whom are ferocious. There are also creatures that have claws, and some that do not. All creatures that have claws are ferocious.

Based only on the information provided above, which one of the following options can be logically inferred with certainty?

• A. All creatures with claws are animals.
• B. Some creatures with claws are non-ferocious.
• C. Some non-ferocious creatures have claws.
• D. Some ferocious creatures are creatures with claws.

Hint:

Use set relations: “All A are B” \(\Rightarrow\) \(A \subseteq B\); “Some A are B” \(\Rightarrow\) \(A\cap B \neq \varnothing\). Existence of a clawed creature + “claws \(\subseteq\) ferocious” \(\Rightarrow\) \( (\text{claws})\cap(\text{ferocious}) \neq \varnothing \).

Answer 1

The Correct Option is D

Given facts:
1) All animals are ferocious. \(\Rightarrow\) Animals \(\subseteq\) Ferocious.
2) There exist creatures with claws and creatures without claws. \(\Rightarrow\) At least one creature has claws.
3) All creatures with claws are ferocious. \(\Rightarrow\) Claws \(\subseteq\) Ferocious.
Check options:
(A) Not implied; clawed creatures could be non-animals. \(\Rightarrow\) Cannot be inferred.
(B) Contradicts (3). \(\Rightarrow\) False.
(C) Contradicts (3). \(\Rightarrow\) False.
(D) From (2) and (3), at least one creature is both ferocious and clawed. \(\Rightarrow\) True.
\[ \boxed{\text{(D) Some ferocious creatures are creatures with claws.}} \]