Question:
For two sets A and B, let AΔB denote the set of elements which belong to A or B but not both. If P = {1,2,3,4}, Q = {2,3,5,6,}, R = {1,3,7,8,9}, S = {2,4,9,10}, then the number of elements in (PΔQ)Δ(RΔS) is
For two sets A and B, let AΔB denote the set of elements which belong to A or B but not both. If P = {1,2,3,4}, Q = {2,3,5,6,}, R = {1,3,7,8,9}, S = {2,4,9,10}, then the number of elements in (PΔQ)Δ(RΔS) is
Updated On: Sep 30, 2024
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- 7
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The Correct Option is B
Solution and Explanation
The correct answer is (B):
P = {1,2,3,4} and Q = {2,3,5,6,}
PΔQ = {1,4,5,6}
R = {1,3,7,8,9} and S = {2,4,9,10}
RΔS = {1,2,3,4,7,8,10}
(PΔQ)Δ(RΔS) = {2,3,5,6,7,8,10}
Thus, there are 7 elements in (PΔQ)Δ(RΔS)
hence, 7 is the correct answer.
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