Question

For the SOP expression $A\overline{B}C + \overline{A}BC + AB\overline{C}$, how many 1s are in the truth table’s output column?

• A. 1
• B. 2
• C. 3
• D. 5

Hint:

Count how many unique input combinations satisfy each term in the SOP expression.

Answer 1

The Correct Option is C

We will evaluate each minterm:
$A\overline{B}C$ is 1 for: A=1, B=0, C=1 → (101)
$\overline{A}BC$ is 1 for: A=0, B=1, C=1 → (011)
$AB\overline{C}$ is 1 for: A=1, B=1, C=0 → (110)
These are 3 distinct minterms. Hence, output is 1 at 3 combinations.