For the reaction S O 2 + 1 2 O 2 = S O 3 , if we write K p = K c ( R T ) x , then x becomes

Explanation: K p = K C ( R T ) x x = ( ∑ n ( g ) ) p − ( ∑ n ( w ) ) R = 1 − 3 2 = − 1 2

Question:

For the reaction $S O_{2} + \frac{1}{2} O_{2} = S O_{3},$ if we write $K_{p} = K_{c} (R T)^{x},$ then $x$ becomes

WBJEE

Updated On: Apr 23, 2024

(A) -1
(B) $- \frac{1}{2}$
(C) $\frac{1}{2}$
(D) 1

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The Correct Option is B

Solution and Explanation

Explanation:

\begin{array}{r} K_{p} = K_{C} (R T)^{x} \\ x = {(\sum n_{(g)})}_{p} - {(\sum n_{(w)})}_{R} \\ = 1 - \frac{3}{2} = - \frac{1}{2} \end{array}

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