Question:

For the isoelectronic series \(S^{2-}, Cl^{-}, Ar, K^{+}\) and \(v\), which species requires the least energy to remove an outer electron?

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In isoelectronic species, the species with the most negative charge or least nuclear charge is easiest to ionize.
Updated On: Apr 1, 2025
  • \(S^{2-}\)
  • \(Cl^{-}\)
  • Ar
  • \(K^{+}\)
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The Correct Option is A

Solution and Explanation

In the isoelectronic series, the species with the least nuclear charge (lowest effective nuclear charge) will require the least energy to remove an electron. Since \(S^{2-}\) has the most electrons and the smallest nuclear charge, it will require the least energy to remove an outer electron. Thus, the correct answer is (a) \(S^{2-}\).
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