Let's solve the problem of finding the number of intersection points between the two curves represented by the functions:
Finding the intersection points involves solving the equation:
\(x^2 = x \sin x + \cos x\)
This equation can be rearranged to:
\(x^2 - x \sin x - \cos x = 0\)
Check for potential intersection points by substituting simple values of \(x\).
Substitute \(x=0\):
\(0^2 = 0 \cdot \sin 0 + \cos 0\)
\(0 = 1\)
This is false, so \(x=0\) is not an intersection point.
Try \(x=1\):
\(1^2 = 1 \cdot \sin 1 + \cos 1\)
\(1 \neq \sin 1 + \cos 1\)
This is not an intersection point either.
Identify intersection points graphically or numerically, as analytic solutions might not be easily derivable.
Graphical analysis or a numerical solver would show that there are exactly two points where these curves intersect for \(x \in \mathbb{R}\).
Thus, the number of intersection points between the given curves is \(n = 2\).
The correct answer is 2, as detailed above.