For spontaneity of a cell, the correct statement is (C) \(ΔG = -ve.\)
The spontaneity of a cell reaction is determined by the Gibbs free energy change \((ΔG)\) of the reaction.
A negative \( ΔG\) indicates that the reaction is spontaneous, meaning it can occur without the input of external energy. Therefore, for spontaneity, we require \(ΔG\) to be negative.
Option A: \((ΔG = +ve, ΔE = +ve)\) is incorrect because a positive \(ΔG\) and positive \(ΔE\) indicate a non-spontaneous reaction.
Option B: \((ΔG = 0, ΔE = 0)\) is incorrect because a \(ΔG\) of zero indicates that the reaction is at equilibrium, not necessarily spontaneous.
Option D: \((ΔG = -ve, ΔE = 0)\) is incorrect because while a negative \(ΔG\) indicates spontaneity, the value of \(ΔE\) can be non-zero. The cell potential \((ΔE\)\()\) is related to \( ΔG\) through the equation \(ΔG = -nFΔE\), and ΔE can have a non-zero value for spontaneous reactions.
Therefore, the correct statement for spontaneity of a cell is \(ΔG = -ve\), indicating a negative Gibbs free energy change.
For a cell reaction to be spontaneous, the Gibbs free energy change (ΔG) must be negative.
The relation between Gibbs free energy and cell potential is:
ΔG = –nFE
where,
n = number of electrons
F = Faraday constant
E = cell potential (electromotive force)
If ΔG is negative, then E must be positive, indicating a spontaneous reaction.
Correct Answer: ΔG = -ve
Concentration of KCl solution (mol/L) | Conductivity at 298.15 K (S cm-1) | Molar Conductivity at 298.15 K (S cm2 mol-1) |
---|---|---|
1.000 | 0.1113 | 111.3 |
0.100 | 0.0129 | 129.0 |
0.010 | 0.00141 | 141.0 |
Column I | Column II |
---|---|
i. Lead storage cell | d. Inverter |
ii. Mercury cell | b. Apollo Space Programme |
iii. Dry cell | c. Wrist watch |
iv. Fuel cell | a. Wall clock |
You are given a dipole of charge \( +q \) and \( -q \) separated by a distance \( 2l \). A sphere 'A' of radius \( R \) passes through the centre of the dipole as shown below and another sphere 'B' of radius \( 2R \) passes through the charge \( +q \). Then the electric flux through the sphere A is