Question:

For real $x,$ let $f (x) = x^3 + 5x + 1,$ then

Updated On: Jun 23, 2023
  • f is one-one but not onto R
  • f is onto R but not one-one
  • f is one-one and onto R
  • f is neither one-one nor onto R
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The Correct Option is C

Solution and Explanation

Given $f (x) = x^3 + 5x + 1$ Now $f '\left(x\right)=3x^{2}+5 > 0, ?x ?R$ $\therefore f \left(x\right)$ is strictly increasing function $\therefore$ It is one-one Clearly, $f\left(x\right)$ is a continuous function and also increasing on R, $Lt_{x\rightarrow-\infty}\,f \left(x\right)=-\infty$ and $Lt_{x\rightarrow\infty}\,f \left(x\right)=\infty$ $\therefore f\left(x\right)$ takes every value between $-8$ and $8$ . Thus, $f\left(x\right)$ is onto function.
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions