Question:

For i = 1\sqrt{-1}, the sum of ((3-3 ++ 4ii)) ++((43i)-4-3i) is equal to

Updated On: Oct 14, 2024
  • 1i-1-i
  • 1+i-1+i
  • 7+i-7+i
  • 7i-7-i
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The Correct Option is C

Solution and Explanation

To find the sum of the complex numbers ((3-3 ++44ii)) and((43i)-4-3i)we can add the real parts and the imaginary parts separately
Real parts:
3+(4)=7-3+(-4)=-7
Imaginary parts:
4i+(3i)=1i4i+(-3i)=1i or simply ii
The sum is:7+i-7+i
So the correct option is (C):7+i-7+i
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