Question:
For $H_3PO_3\, and\, H_3PO_4,$ the correct choice is
For $H_3PO_3\, and\, H_3PO_4,$ the correct choice is
Updated On: Jun 14, 2022
- $H_3PO_3$ is dibasic and reducing
- $H_3PO_3$is dibasic and non-reducing
- $H_3PO_4$is tribasic and reducing
- $H_3PO_3$is tribasic and non-reducing
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The Correct Option is A
Solution and Explanation
$H _{3} P O _{3}$ is a dibasic acid as it has 2 number of replaceable OH groups(Dibasic) attached to phosphorous. The oxyacids of phosphorous are reducing agents. $H _{3} PO _{3}$ is a good reducing agent than $H _{3} PO _{4}$. The reducing nature of these acids is based on the no of hydrogen atoms bonded to the central metal atom. As more number of $H$ attached to phosphorous more is its reducing nature. In the case of $H _{3} P O _{3}$, there is one $P - H$ bond which is responsible for it's reducing character whereas there is no such bonding in case of $H _{3} P O _{4}$.
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family