For carbylamine reaction, we need hot alc. KOH and
- any primary amine and chloroform
- chloroform and silver powder
- a primary amine and an alkyl halide
- a mono alkyl amine and trichloromethane
The Correct Option is A
Solution and Explanation
very unpleasant smell. $CH_3 CH_2 NH_2 + CHCI_3 + 3KOH \xrightarrow {Warm}$ $\hspace50mm CH_3 CH_2 NC + 3KCI + 3H_2O$
Top Questions on Amines
Total number of molecules/species from the following which will be paramagnetic is ………. \[ O_2, O_2^+, O_2^-, NO, NO_2, CO, K_2[NiCl_4], [Co(NH_3)_6]Cl_3, K_2[Ni(CN)_4] \]
The total number of compounds from below when treated with hot KMnO4 giving benzoic acid is:
The major product of the following reaction is:
- The purification method based on the following physical transformation is: \[ {Solid} \xrightarrow{{Heat}} {Vapour} \xrightarrow{{Cool}} {Solid} \]
- Consider an elementary reaction: \[ A(g) + B(g) \rightarrow C(g) + D(g) \] If the volume of the reaction mixture is suddenly reduced to \( \frac{1}{3} \) of its initial volume, the reaction rate will become \( x \) times of the original reaction rate. The value of \( x \) is:
Questions Asked in NEET exam
- Given below are two statements:
Statement I: Both [Co(NH3)6]3+ and [CoF6]3- complexes are octahedral but differ in their magnetic behaviour.
Statement II: [Co(NH3)6]3+ is diamagnetic whereas [CoF6]3- is paramagnetic.
In the light of the above statements, choose the correct answer from the options given below:- NEET (UG) - 2024
- Electronic configuration of atoms and ions
- \(^{290}_{82}X\stackrel{\alpha}{\rightarrow}Y\stackrel{e^+}{\rightarrow}Z\stackrel{\beta^-}{\rightarrow}P\stackrel{e^-}{\rightarrow}Q\)
In the nuclear emission stated above, the mass number and atomic number of the product Q respectively, are :- NEET (UG) - 2024
- Nuclear physics
- Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector \(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :- NEET (UG) - 2024
- Magnetic Field
- Choose the correct circuit which can achieve the bridge balance.
- NEET (UG) - 2024
- Digital Electronics and Logic Gates
- In a Vernier caliper, \(N+1\) divisions of vernier scale coincide with \(N\) divisions of main scale. If 1 MSD represents 0.1 mm, the vernier constant (in cm) is:
- NEET (UG) - 2024
- Units, Dimensions and Measurements
Concepts Used:
Amines
Amine is a type of compound which is derived from ammonia (NH3). According to Organic chemistry, they are basically classified as the functional groups of the organic nitrogen compounds that contain nitrogen atoms with a lone pair.
Amine - Types
Primary Amines:
It is formed when one hydrogen atom in ammonia is substituted by an alkyl or aromatic group. Amino acids and methyl amine are the best examples that why aromatic amines include aniline.
Secondary Amines:
Amines that have two organic substitutes either alkyl or aryl ones or both and are bound to the nitrogen together with one hydrogen are termed as secondary amines. For Example, Dimethylamine.
Tertiary Amines:
Tertiary Amines are the amines where the nitrogen consists of three organic substitutes. For example, Trimethylamine and EDTA.