Question:

For any arbitrary motion in space, which of the following relations is true? (The average stands for average of the quantity over the time interval $t_1$ to $t_2$)

Updated On: Jul 6, 2022
  • $\vec{v}_{average}=\frac{1}{2}\left[\vec{v}\left(t_{1}\right)+\vec{v}\left(t_{2}\right)\right]$
  • $\vec{v}_{average}=\frac{\vec{r}\left(t_{2}\right)-\vec{r}\left(t_{1}\right)}{t_{2}-t_{1}}$
  • $\vec{v}\left(t\right)=\vec{v}\left(0\right)+\vec{a}t$
  • $\vec{r}\left(t\right)=\vec{r}\left(0\right)+\vec{v}\left(0\right)t+\frac{1}{2}\vec{a}t^{2}$
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The Correct Option is B

Solution and Explanation

The relation (b) is true, others are false because relations (a), (c) and (d) hold only for uniformly accelerated motion.
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration