Question

For an ideal gas, a cyclic process ABCA as shown in the P–T diagram. When represented in P–V plot, it would be 

• A. Option a
• B. Option b
• C. Option c
• D. Option d

Hint:

Graph conversions: Constant P ⇒ horizontal in P–V. Constant T ⇒ hyperbola. }

Answer 1

The Correct Option is C

Concept:
Use ideal gas law:
\[ PV = nRT \]

Step 1: Analyse segments in P–T graph
- AB: horizontal line ⇒ constant pressure (isobaric).
- BC: vertical line ⇒ constant temperature (isothermal).
- CA: slanted line ⇒ linear P–T relation ⇒ neither iso-P nor iso-T.

Step 2: Convert to P–V plot
- Isobaric (AB) ⇒ horizontal line in P–V.
- Isothermal (BC) ⇒ hyperbola in P–V.
- Remaining segment (CA) closes loop.

Step 3: Match graph
Only option with:
- Straight horizontal AB
- Curved BC
is (C).