Question

For an ideal diode, the current in the following arrangement is

• A. 10 A
• B. 10 mA
• C. 20 mA
• D. 1 mA

Hint:

For an ideal diode, the forward voltage drop is zero. Use Ohm's law to calculate the current when the diode is forward biased.

Answer 1

The Correct Option is B

Step 1: Understanding the circuit.
For an ideal diode, the current will flow if the diode is forward biased. The voltage across the resistor is the difference between the supply voltage and the diode voltage. Since the diode is ideal, its forward voltage drop is considered zero. The current \( I \) through the resistor can be found using Ohm's law: \[ I = \frac{V}{R} \] where \( V = 2V - (-2V) = 4V \) is the total voltage across the resistor, and \( R = 400 \, \Omega \) is the resistance. Step 2: Calculating the current.
\[ I = \frac{4V}{400 \, \Omega} = 0.01 \, \text{A} = 10 \, \text{mA} \] Step 3: Conclusion.
Thus, the current is 10 mA, which is option (B).