Question:

For an ellipse, the foci are \( F(3,0) \) and \( F'(-3,0) \). If the length of the minor axis is 8, then the length of the major axis is equal to

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For an ellipse, use \( c^2 = a^2 - b^2 \) to find the semi-major and semi-minor axes.
Updated On: Mar 6, 2025
  • \( 16 \)
  • \( 15 \)
  • \( 14 \)
  • \( 12 \)
  • \( 10 \)
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The Correct Option is

Solution and Explanation

For an ellipse, the standard relation holds: \[ c^2 = a^2 - b^2 \] where: - \( a \) is the semi-major axis, - \( b \) is the semi-minor axis, - \( c \) is the focal distance (distance from center to foci). From the given foci: \[ c = 3 \] Given that the minor axis is 8, we have: \[ b = \frac{8}{2} = 4 \] Using the equation: \[ c^2 = a^2 - b^2 \] \[ 3^2 = a^2 - 4^2 \] \[ 9 = a^2 - 16 \] \[ a^2 = 25 \] \[ a = 5 \] Since the major axis length is \( 2a \): \[ {Major Axis} = 2 \times 5 = 10 \] 
Final Answer: \[ \boxed{10} \]

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