Question

For a hollow spherical shell, potential \( V \) changes with respect to distance \( r \) from the centre. Which graph from the following represents this?

• A.

  

• B.

  

• C.

  

• D.

  

Hint:

Remember: Inside a hollow conducting spherical shell, electric potential is constant; outside, it follows inverse law \( V \propto \frac{1}{r} \).

Answer 1

The Correct Option is B

For a hollow spherical shell (conducting), the electric potential inside the shell (i.
e.
, for \( r<R \)) is constant and equal to the potential at the surface.
\[ V_{\text{inside}} = \frac{1}{4\pi \varepsilon_0} \cdot \frac{Q}{R} \quad (\text{constant}) \] For \( r \geq R \), the shell behaves like a point charge at the center, and potential decreases as: \[ V_{\text{outside}} = \frac{1}{4\pi \varepsilon_0} \cdot \frac{Q}{r} \] Thus, the correct graph is constant from the center to the surface, then falling as \( \frac{1}{r} \).