Question

For a body moving along a straight line, the following v-t graph is obtained.

According to the graph, the displacement during

• A. Uniform acceleration is greater than that during uniform motion.
• B. Uniform acceleration is less than that during uniform motion.
• C. Uniform acceleration is equal to that during uniform motion.
• D. Uniform motion is zero.

Answer 1

The Correct Option is B

The graph depicts velocity (v) as a function of time (t). The area under a velocity-time graph represents the displacement of the object. In this case, the motion can be divided into three distinct phases:

The dotted lines on the graph are a visual aid. They illustrate that the area of the triangle representing uniform acceleration (Part 1) could be combined with the triangular area of the deceleration phase (Part 3). These two triangular areas combined create a rectangular area with the same base and height as the rectangle representing uniform motion (Part 2).

Since the acceleration triangle (Part 1) only accounts for half of that rectangular area, the displacement during the period of uniform acceleration is less than the displacement during the period of uniform motion.

The correct answer is Uniform acceleration is less than that during uniform motion.