For a BCC structure, if a = 351 pm, find r. Lithium forms a BCC structure having an edge length of a unit cell 351 pm, then find the atomic radius of lithium.
For a BCC (body-centered cubic) structure, the relationship between the lattice constant (a) and the atomic radius (r) is:
a = 4√(2)r/3 Solving for r, we get: r = (3a/4√(2)) Substituting the given value of a = 351 pm (or 3.51 Å), we get: r = (3 x 3.51 Å) / (4√(2)) r ≈ 1.53 Å
Therefore, the atomic radius of lithium in its BCC structure is approximately 1.53 Å.
Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions.
Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;