Question:

For $14\, g$ of $CO$ the wrong statement is :

Updated On: Aug 1, 2022
  • it occupies 2.24 litres at NTP
  • it corresponds to $ \frac{1}{2} $ mole of CO
  • it corresponds to same mole of CO and nitrogen gas
  • it corresponds to $ 3.01\times 10^{23}$ molecules of CO
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The Correct Option is A

Solution and Explanation

We know that $14\, gm CO =\frac{14}{28}=0.5\, mol$ Therefore, it corresponds to $\frac{1}{2}$ mole of CO and nitrogen gas. $0.5$ mol is equivalent to $3.01 \times 10^{23}$ molecules.
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Concepts Used:

Stoichiometry

Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products, leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of the products can be empirically determined, then the amount of the other reactants can also be calculated.

Stoichiometry helps us determine how much substance is needed or is present. Things that can be measured are;

  1. Reactants and Products mass
  2. Molecular weight
  3. Chemical equations
  4. Formulas

​​Stoichiometric Coefficient

The Stoichiometric coefficient of any given component is the number of molecules and/or formula units that participate in the reaction as written.

Mole Ratios

The mass of one mole of a substance in grams is called molar mass. The molar mass of one mole of a substance is numerically equal to the atomic/molecular formula mass.