To determine the number of molecular orbitals for the π electrons in 1,3-butadiene, we can follow these steps:
- 1,3-Butadiene is a conjugated diene with the molecular formula \(C_4H_6\). It has a chain of four carbon atoms, two of which are connected in succession by double bonds.
- In conjugated systems, the number of molecular orbitals formed is equal to the number of atomic orbitals involved, which in this case refers to the p orbitals that participate in π-bonding.
- Each carbon atom in the double bond contributes a p orbital for the formation of π molecular orbitals. Therefore, for 1,3-butadiene, there are four carbon atoms, each providing one p orbital for π bonding.
- These four p orbitals combine to form four π molecular orbitals: two bonding and two anti-bonding. These are designated as \(π_1, π_2, π_3^*,\) and \(π_4^*\), where \(π_1\) is the lowest energy (most stable) bonding orbital, \(π_2\) is another bonding orbital, and \(π_3^*\) and \(π_4^*\) are antibonding orbitals.
Therefore, the correct answer is 4:
- Option 2: 4 - This is the correct number of molecular orbitals formed by the p orbitals involved in the π-bonding of 1,3-butadiene.
- Options 1, 3, and 4 (2, 6, 8 respectively) are incorrect because they do not match the number of available p orbitals in 1,3-butadiene.
Hence, for 1,3-butadiene, there are four molecular orbitals formed for π electrons.